Recent content by ddoucet

I'm now using the moment of inertia of a cylinder on it's transversal axis : I = 1/12 * mh^2 + 1/4 * mr^2 But since the mass of a pin is less uniformly dispersed than the one of a cylinder, I would have think that it's inertia would be lower.

Any idea about an integration method that I could use ?

The pin height = 38.1 cm The pin mass center height : 14.68m I think that it's possible to have a very good approximation of the bowling pin volume by using few spheres. In my application, the pins are represented by 6 spheres.

Sorry about this lack of precision : around the horizontal axis.

Hi, I need to know the moment of inertia of a bowling pin. I'd like to know how to calculate it. I would prefer an approximation formula according to the mass of the pin instead of an integration method. Thank you