Recent content by De_Dre01

Homework Statement Homework Equations αt = r α The Attempt at a Solution ωi = 0 rad/s αt = 2.00 rad/s2 r = 112 m θ = ? at a = 6.80 m/s2 I'm not exactly sure where to begin. Help is appreciated.

Homework Statement [/B] Person A fires a 222 g arrow towards an archery target at a speed of 109 m/s. Person B shoots a 190. g arrow moving in the same direction. This arrow moves with a speed of 290. m/s, catches up, and then collides with Person A's arrow. If the arrows collide in a...

Ahah. Got it now. Thanks, was really helpful.

Ok I calculated distance in the x by tan16 = 78.4/x now apply work formula?

So now I have: W = FΔdcosθ = (93N)(78.4)cos(164) = -7008.75 J Correct?

I thought you could move the vector around. In that case, would the angle be 90+74°?

Even if you do that, can't you move the vector around and displace the tail of the second vector to the head of the first vector? Resulting in the same angle of 16°*?

The angle would be less than 90 then.

I might be picturing the problem incorrectly. The wind would be directed west while displacement would be down the hill, correct?

The angle between the Force and Distance. Would it be 16° because of the Z Pattern?

74°?

W = FΔdcosθ.

I must consider the incline plane, should I not? Would I need to find the adjacent side? Edit: Would the distance be 78.4/tan16?

Horizontal wind force opposing the skateboarder's motion.

Opposite = 78.4 m Angle = 16.0°Solving for hypothenuse: sin16° = 78.4/h h = 78.4/sin16° Is this not correct?