Recent content by dearcomp

We have dx/dt =2v*(-x) / sqrt((-x)^2+(vt-y)^2) & dy/dt = 2v*(vt-y) / sqrt((-x)^2+(vt-y)^2) we can get dy/(vt-y) = -dx/x with some math, and when I integrate both sides, I get vt-y = x*e^c and the question asks for y so, the answer would be y = vt-x*e^c wouldn't it? My question comes...

So, dx = 2v*(-x) / sqrt((-x)^2+(vt-y)^2) dt and dy = 2v*(vt-y) / sqrt((-x)^2+(vt-y)^2) dt and the question asks dy. Am I right?

The direction of N at time t would be the vector from N to M, which is the vector from (x,y) to (0,vt) = -x.i + (vt-y).j I think, dx would be 2v*(x component of the direction vector) which is 2v*(-x) respectively, dy would be 2v*(vt-y) ?

Hello again, I come up with a new question which I can't express as a differential equation form. 2 cars start on x axis, M at the origin and N at the point (36,0) Suppose: M moves along the y axis, and N moves directly toward M at all times, and N moves twice as fast as M. Q) How far will...

Re: First Order Non Linear Ordinary D.E. Indeed, even wolfram can't handle this problem. I'm trying to use WolframMathematica but I can not make it understand the question because I'm not familiar with it... There are no hints, suggestions related to the question :(

Re: First Order Non Linear Ordinary D.E. Yes Sudharaka solved a different D.E This is the exact problem with the corrected parantheses.. (x*y*sqrt(x^2-y^2) + x)*y' = (y - x^2*(sqrt(x^2-y^2))) Thank you in advance

Hello people, I couldn't solve the given D.E by using exact d.e & substitution method :( Thanks in advance. (x*y*sqrt(x^2-y^2) + x)*y' = (y - x^2*(sqrt(x^2-y^2) ) gif file of d.e can be found in the attachments part.