That is a likely possibility, however, there are other students that may be in need of such information and look at older postings as well. This may not help this ONE student in particular, but it may help many others. Why would the older forum threads still be in existence if they were not open...
Integrate a = dv/dt to get at = v-v(initial). Solve for t and plug in the numbers.
You should get t = 323 / (6 + 40) = 7 seconds.
You would normally be able to solve the integral you have in the end with basic trig substitution (calculus 2) but since you have an s in front of the 12 you can...
You already solved it. Just plug your c(y) into F. Your F is x^2 + 3x + c(y) after you integrated the M term. Plug c(y) back into F and you get x^2+3x+y^2-2y.
...you forgot mgsin(theta) in your original "Fnet" equation. Include mgsin(theta) and you should get the acceleration. --------> ma = T - F - mgsin(theta)
If it helps any...
Once you get your result from long division (should be 4x+4-(4x/x^2-25)), multiply through by x^2-25 on both sides. This will leave you with 4x^3+4x^2-96x-100 = 4x(x^2-25)+4(x^2-25)-4x.
Now set x = 0 , so A = 4
Now set x = 5 , so C = -1
Now set x = 1 , so B = -2 ( don't...