Finding d limit of the absolute value of x-3, divided by x-3, for x approuches 0.
lim [x-3]/(x-3)
x->0
Principle [x-3]= {(x-3) if x>4}
{-(x-3) if x<4}
Remember that limit olny exist only if the limit from the negetive side is equal to the limit from...