Recent content by Deleote

Thats what I believed to be true also but that would yield an answer of 60 m/s for the magnitude of the final speed which is incorrect... I attempted to solve using that method...3m(c)v(c)=m(a)*90 m/s + m(b)*90 m/s.

1. Ok, I've been working on this problem for ever and it seems easy but I know that there is something wrong. A vessel at rest explodes, breaking into three pieces. Two pieces, having equal mass, fly off perpendicular to one another with the same speed of 90 m/s. One goes along the negative...