ahhh i totally forgot i could just divide both sides by it
insted i was doing something else i learned recently... damnit so many formulas! lol
thank you a lot.
http://img123.imageshack.us/img123/2411/118dj.th.png
that's the problem.
i've done this;
{Fx = T2 - T1cos60 = 0
and
{Fy = T1sin60 - 58N = 0
then to find T2 i thought i could do this;
T1sin60 = 58N
to
T1=(sin^-1)60 + 58N
but the answer is apparently wrong... so i must not...
alright, I'm having trouble finding a formula to answer this problem.
a 58N weight is being suspended by 2 cables. the cable on the left side is horizontal, while the other cable is at a 60' angle.
What is the tension of the right side cable? (T1)
What is the tension of the left side...