Recent content by Demmy

sir, I tried all of your equation I didn't got the correct answer. and I have a question in number 2 in the equation "d5 = d2 + v2 * (3 secs)" isn't that suppose to be "a" or acceleration instead of "v" velocity? because I checked it.

it didn't say that the the puck has stop moving, it just said that same force is applied at t=5s

no sir, english is my third language

I tried to find the distance for 5s, so I used the same accelerationso my equation is (1.563*(5^2))/2 then I got 19.5375

ahm sir, sorry bout the convertion thingy, I don't get is sir.

I have another question, I got letter a) but why is the unit I got is m/(s^2) the answer should be m/s, but I got the right answer. so I just randomly thought about converting the acceleration to velocity, because the unit of acceleration is m/(s^2) and the velocity is m/s, but if I do that in...

@Jakeus314: I don't think they are different sir, ahm, already got the answers for 2s sir

sir, I got the final velocity I converted a= 1.563 m/(s^2) to m/s so I got v= 3.13 m/s then I used it as my vinitial to get my vfinal using the equation you gave me, my vfinal= 6.256 m/s but when I tried to substitute that to the 2nd equation you gave me, I didn't got the correct answer.

ahm, sir, where would I get my vinitial?

Btw, here are the answers a) 3.13m, 3.13m/s b) 21.9m, 6.25m/s

Given: F=0.250 N m=0.160 kg F=ma a=F/m leads to: a=0.250/0.160 i got a= 1.5625 then I used the formula a=(2s)/(t^2) to get the distance then I got s=3.13 m then, couldn't solve for b, please help

Please help -- Motion of a hockey puck Homework Statement Hi guys, can you please help me answer this problem? A hockey puck with mass 0.160 kg is at rest at the origin on the horizontal, frictionless surface of the rink. At time t=0 a player applies a force of 0.250 N to the puck...