Recent content by depizixuri
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Undergrad How to Approach Solving 2y+(y')^2+ax^b=0?
No. It doesn't works. If I choose r=1, then A(x)=constant (which is correct), but R(x) is variable using this method.- depizixuri
- Post #10
- Forum: Differential Equations
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Undergrad How to Approach Solving 2y+(y')^2+ax^b=0?
It helps. It says that for dimension ##r=-1: c_1=36\pi## and helps me think out the box of treating b as a variable. Actually, those values for a and b have 10 different solutions for y(x). I'm not sure about what to make of it. Maybe one of those solutions is x². Thanks you.- depizixuri
- Post #9
- Forum: Differential Equations
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Undergrad How to Approach Solving 2y+(y')^2+ax^b=0?
Why you asked? Does the answer makes a difference? Does it help to classify the problem or know what area should it be related? Can you tell me at least what information does that gives or could give to you? I ask because it may help me to investigate it.- depizixuri
- Post #7
- Forum: Differential Equations
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Undergrad How to Approach Solving 2y+(y')^2+ax^b=0?
Do anybody knows any more specialized forum where I can ask about this?- depizixuri
- Post #6
- Forum: Differential Equations
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Undergrad How to Approach Solving 2y+(y')^2+ax^b=0?
Ok. I was reading about Hausdorff dimension, and I wanted to find a continuous, compact surface, without holes, with dimension 1 \leq r \leq 2. So, the area function A(x), to have a Hausdorff dimension r, must satisfy this equation: \epsilon A_{(\frac{x}{\epsilon})} = \epsilon^r A_{(x)}...- depizixuri
- Post #5
- Forum: Differential Equations
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Graduate Need help solving a differential equation
Sorry, you are right. Is not trivial. I was wrong. Is better to use Laplace transform, and even then you get a nasty work. Your solution is $$ f(x) = \left ( c_1 \Gamma_{\left(\frac{B}{A g i}+1\right)} J_{\left({\frac{B}{A g i}} , \frac{2 \sqrt{A C e^{g i x}}}{A g i}\right)}+c_2...- depizixuri
- Post #9
- Forum: Differential Equations
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Graduate Can someone walk me through solving a PDE numerically?
An easy way to calculate numerically is \frac{\Delta\rho}{ \Delta t } = - \frac{\Delta v_{max}(\rho - \frac{\rho^2}{\rho_{max}})}{\Delta x} So, if you know all the values at a time t, and because \Delta\rho = \rho_{t+1} - \rho_{t}, then you can calculate \rho_{t+1} this way: \rho_{t+1} =...- depizixuri
- Post #13
- Forum: Differential Equations
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Graduate Need help solving a differential equation
The exponential is easy to deal because exponents are added on multiplication.- depizixuri
- Post #7
- Forum: Differential Equations
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Graduate Need help solving a differential equation
There are many ways to solve it without previous knowledge of the solution. One is to make a Laplace or Fourier transform. It turns the problem into a very simple equation without any derivatives. You solve it, and reverse the transform.- depizixuri
- Post #6
- Forum: Differential Equations
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Graduate Need help solving a differential equation
It is a trivial solution taught at any basic course of differential equations. If you have a differential equation written as \sum_{n=0} ^m c_n \frac{\mathrm{d} ^n f_{(x)}}{\mathrm{d} x^n}=0, then is is known that the solution is an exponential function.- depizixuri
- Post #4
- Forum: Differential Equations
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Graduate Need help solving a differential equation
The solution is f_{(x)}=e^{a+bx}. You need to find the complex constants a and b.- depizixuri
- Post #2
- Forum: Differential Equations
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Undergrad How to Approach Solving 2y+(y')^2+ax^b=0?
Is not home assignment. Is personal curiosity. I want it to find the radius of a surface of revolution from which I only know the area. After some manipulation, I reduced the equation to this form. ¿Do you want to know how I got it? Meanwhile I have been told to look on the Weierstrass...- depizixuri
- Post #3
- Forum: Differential Equations
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Undergrad How to Approach Solving 2y+(y')^2+ax^b=0?
I tried to solve this differential equation: 2y+(y')^2+ax^b=0 ...but don't know what to do with it. Don't know what variable substitution to use. Tried Taylor series, but I get horrible nonlinear equations for the coefficients. Tried Mathematica, but it doesn't answer anything: In[20]:=...- depizixuri
- Thread
- Differential equation
- Replies: 10
- Forum: Differential Equations
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Is This Forum Good for Math Help as an Aspie?
I'm an aspie, and I had been asked to introduce myself after registering. That's awkward and unnecessary to me. I don't know what's the point. I'm looking for help with math.- depizixuri
- Thread
- Replies: 2
- Forum: New Member Introductions