Recent content by Deployment

So could it be this simple.. 1.) The weight of the table is 68.11N, which can be converted into 6945.2871 grams. 2.) If you divide the weight of the table (In grams) by 4, you get the amount of weight that must be exerted on EACH bucket. Which is 1736.321775 grams. 3.) Now we have to factor in...

So we were coming to the conclusion today that what if you just took the weight of the table and divided it by 4...As long as each bucket is pulling with the same amount of force of course. The only concept that I keep over-thinking is that the ropes go through the pulley from the buckets to the...

The buckets and table are all going to have to meet at the same point in the air. By putting the same amount of weight in each bucket, the buckets are taken care of and will all be equal. The question is how much weight. I have the logic and can explain it to anyone, the equations are just...

Firstly, sorry for placing this in the wrong section..I am just learning my way around here. Secondly, this is 100% possible, with no tricks such as the table being attached to the wall, etc. We are currently doing this in physics class, and I was wondering if the geniuses at Physics Forums had...

Hello Physics Forums, Deployment here. After browsing the internet I came across this photo.. I have been pondering and pondering on how this is actually possible. If you think about it, the buckets are actually holding down the table. Does anybody have any idea how you would conduct...