oh I just read this last part so my answer was correct then? It does fall between those two values, but that's the highest value in that range you gave me. The problem asks for the "minimum value" of the hanging mass so the 2 kg block remains still as the system moves.
...so confused lol
Ok I finally solved for the hanging mass needed to keep the 2 kg block from not moving, but I got .56 kg. Then I used that to find the net force in the x-direction for the whole system and got -1.2 N. So I'm thinking something went wrong somewhere lol. Basically, I don't know what to do after...
So what you're saying is I should treat the two blocks as one?
And what do you mean by the "internal forces between the blocks"? Like the static friction between them?
Well, first I made the force diagrams and noted the action/reaction pairs. I'll put them on so you can see if I did those right or not. Then, I figured the net force in the y-direction for the 2 kg block had to be equal to 0, so I solved for the Force of block one on block two (F1on2). Then, I...
Yes, I need to find the mass of the hanging block such that it causes the other two blocks to move together, but NOT cause the top block (the one the rope is connected to, the 2 kg one) to move. Hopefully that makes more sense now lol sorry I should have clarified that more.
1. A 1 kg wedge is pulled across a rough floor (uk=0.20) via contact with a 2 kg block as shown below. The shape of the wedge is that of an isosceles right triangle. a rope passes from the 2 kg block and over a mass-less and friction-less pulley and is attached to a hanging mass. Find the...