Recent content by Designman

Cwatters, I think you got it! There is no friction to a body spinning in space, solid or gas.

Any more help would be appreciated. Still stumped.

Yes, the chassis has a damper.

Anybody got some thoughts?

Here is the problem simplified. I think I should have presented the problem like this: A pendulum bob of mass M, and having a rod of no mass and a length D, pivots from a bearing having no friction. A force F is applied tangentially to the pendulum's arc to the mass M. Compute new angle after F...

We have a fixed CG that maintains the body in a horizontal plane when absent of applied torque.

Maybe this will help. Think about the anti-torque rotor on a helicopter. But, instead of being a simple torque moment problem, we have a suspended weight.

The motor is driving an axle which is driving a resistance ( not shown) that generates torque. That torque would spin the body around the axle if the axle was fixed.

Sorry, please ignore previous post. The torque applies a constant torque of 1 / 4 at 4' on a suspended vertical mass. What is the resultant angle after toque is applied?

Lesolee, okay good. The torque is constant at 4' or 1 / 4 x suspended mass. What is the resultant angle after toque is applied?

The axle is driving a resistance with a resultant torque of 2626 ft/lbs

Further, the actual figures I'm working with are T = 2626 ft/lbs Weight = 1750 lbs and 2900 lbs, and D = 4' and 5'.

Clearly, I am in over my head. What I require is a formula where I can plug in torque using ft/lbs, horizontal distance of CG from axle in feet or inches, and weight in pounds. I require degrees from horizontal, and offset of CG to maintain horizontal or another degree. A lab set up with a...

Hi billy. The result. At 90 degrees the applied torque equals the weight of the suspended mass. At 45 degrees, 1/2 the suspended weight. It's a simple mathematical relationship! Thanks for your assistance in getting my head around this.