Okay... So that produces:
x(t) = t2f/2m + t
v(t) = f.t/m
That makes the Lagrangian
L = (m/2)f2t2/m2 + f (t2f/2m + t)
So this is L as nothing but a function of t (and f is constant)
If we integrate this wrt time over ta-tb that should be the answer?
Whoops, that obviously wasn't correct... i made an algebraic mistake while writing the equations down here.
What I meant was simply taking m/2 out of the first term and ma out of the second term since they should be constant:
S = (m/2) ∫v^2dt + (ma) ∫ xdt.
And can you please provide an...
Homework Statement
Find Scl for a particle under constant force f, that is:
L = (m/2)v2 + fx
Homework Equations
S = ∫Ldt
d(∂L/∂q^{.})/dt = ∂L/∂q
The Attempt at a Solution
Apologies if this belongs in the Introductory Physics section. Apologies for terrible formatting...