Recent content by devaluator

Okay... So that produces: x(t) = t2f/2m + t v(t) = f.t/m That makes the Lagrangian L = (m/2)f2t2/m2 + f (t2f/2m + t) So this is L as nothing but a function of t (and f is constant) If we integrate this wrt time over ta-tb that should be the answer?

Whoops, that obviously wasn't correct... i made an algebraic mistake while writing the equations down here. What I meant was simply taking m/2 out of the first term and ma out of the second term since they should be constant: S = (m/2) ∫v^2dt + (ma) ∫ xdt. And can you please provide an...

Homework Statement Find Scl for a particle under constant force f, that is: L = (m/2)v2 + fx Homework Equations S = ∫Ldt d(∂L/∂q^{.})/dt = ∂L/∂q The Attempt at a Solution Apologies if this belongs in the Introductory Physics section. Apologies for terrible formatting...