Recent content by devvaibhav

@blazeatron Thanks. Got it now...

Homework Statement During paddling of a bicycle, the force of friction exerted by the ground on the two wheels is such that it acts (A) Front Wheel -----> Backward | Rear Wheel ------> Forward (B) Front Wheel -----> Forward | Rear Wheel ------> Backward (C) Front and Rear Wheels...

@ PeterO Thanks... The imagination is well written...I understood it now...

@ PeterO (A) is correct (C) is correct too but don't know why? That's why i posted this question. (D)- the original one with but no other assertion can be made with the information given. is not correct. Would you please explain why (B) is not correct and (C) is? Thanks...

Yes i agree with you over the open and closed intervals but i have written the same as printed in the book. And yes the thread name is correct. Its a Multiple Choice Multi Correct Question.

Sorry but (A) is True and (D) is False. By the way its a IIT-JEE question so you got to think upon it a little deeper.

1. A particle of mass m moves on the x-axis as follows. It starts from rest at t=0 from the point x=0 and comes to rest at t=1 at the point x=1. No other information is available about its motion at intermediate times (0<t<1). If α denotes the instantaneous acceleration of the particle, then...

Well ok. So the net result of this discussion is Potentialnet at P = Potential of sphere + Potential of scooped out piece(that has been superimposed, we mean to say we assume it to be scooped and then superimpose it) + Potential of scooped out piece(which is at the top) The last two terms...

Thanks a lot @gneill and @vela @vela You said that potential of big mass with hole = potential of sphere - potential of scooped out piece When we calculate the potential of big mass with hole = potential of sphere - potential of scooped out piece(which is at the top?). The potential which we...

Mass of larger sphere( means the one that is left after scooping out?) = M Are you saying about this sphere? But that is hard to digest. Means -m mass don't makes sense practically..It seems absurd. The mass of sphere(before scooping out) was also M and after scooping out is too M. Please but...

Well i calculated it like this. The mass of volume 4∏R3/3 → M The mass of volume 1 → 3M/4∏R3 Hence the mass of volume 4∏/3(R3- R3/64) → 3M/4∏R3 X 4∏/3(R3- R3/64 = 63M/64 What else do i need to do? Please tell me.

Yes exactly. I think i have treated them as three different objects and the potential due to +m and -m gets canceled. Is my thinking correct?

The Gravitational potential due to m and -m mass spheres will cancel out. So we are left only with the gravitational potential due to larger sphere left part whose mass is 63M/64. Hence the net gravitational potential becomes . Is my answer correct? or is there something still left? Thanks

1. From a solid sphere of radius R and mass M, a small sphere of radius R/4 is scooped out and placed on the surface of the original sphere on a diametrically opposite point as shown in the figure. The gravitational potential of the resulting system at a point P(as shown in the figure) is (Take...

@RTW69 tnx...it was hell simple..i was confused..tnx for it... @Redbelly98 its ok... thanks everyone...