Recent content by Dexter09

I think that both of theE3 and E4 x components are in the positive x direction. Are you able to tell me if I have the vectors at least pointing in the right directions as I described them in post 22? I would try to do what rude man suggested in post 24, but I don't understand how the midpoint...

Ok, now I just feel stupid and defeated. Thanks again for trying to help me.

The Qs are located as described in post 20. In relation to the midpoint of the bottom side of the square, I have vector E1 going from the bottom right +Q toward the midpoint, E2 going from the midpoint to the lower left -Q,E3 extending from the midpoint on an angle in the positive x/negative y...

The book answer is: 1.15 x 10^10 Q/L^2 for two midpoints, and -1.15 x 10^10 Q/L^2 for the other two midpoints. I've tried my numbers in different combinations to see if I can find my sign error, but I just can't figure it out. Coulomb's Law has a +Q in E1 and a -Q in E2, but they both point in...

Aighh. I took so long to type that I was logged out. Here is a quick recap: E1x=4kQ/L^2 = 3.60 x 10^10 Q/L^2 E2x = -4kQ/L^2 = -3.60 x 10^10 Q/L^2 E3x = E3 sin theta = 4kQsqrt5Q/25L^2 = 3.22 x 10^9 Q/L^2 E4x = E4 sin theta = -4kQsqrt5Q/25L^2 = -3.22 x 10^9 Q/L^2 so the x components cancel...

So E1 and E2 both go from the midpoint toward the -Q corner that is to their left. And E3 and E4 each go from the midpoint on diagonals in the positive x direction (their y components cancel out). I got E1x=-4kQ/L^2, E2x=-4kQ/L2, E3x=E4x=4sqrt5kQ/25L^2 But the sum of all the x-components still...

Away from positive, toward negative.

Now I am completely confused. Should I even be drawing electric field vectors from the midpoint, if it is not a charge?

I had +Q(1) in the upper left and lower right, and -Q(2) - in upper right and lower left. I was considering the midpoint on the bottom of the square (with -Q(3) on its left and +Q(4) on its right. I drew vectors E1 from -Q(3) to the midpoint, vector E2 from the midpoint toward +Q(4), and E3 on...

Actually, I was a little unsure of how to treat the q for the midpoint since I didn't think it would have a net charge. I just used Coulomb's Law and made E = kQ/r^2 (and since the r is L/2, it became E=4kQ/L^2)

And since the vectors were completely horizontal, there is no y component. So the x-components are equal to the total E for each.

I had the midpoint with -Q on the left, and +Q on the right. I drew my E1 vector from the midpoint toward +Q, and the E2 vector from the -Q toward the midpoint.

θHomework Statement What would be the electric field on the midpoint of each side of a square with point charges of +Q on diagonal corners and -Q on diagonal corners? Homework Equations E=kQ/r^2 Ex=Ecosθ Ey=Esinθ The Attempt at a Solution Considering the midpoint of the side at...