although this doesn't seem right when i plug in the given variables in part D
iron M = 250g, ice m = 48g and the specific heat of iro in 0.44J / g ºC.
given Lf ice= 334J/g
Ti iron = (-48x334)/(0.44x250)-0 = -145.7454545 ? that can't be right
thank u so much,
so after well cancel out n simplify is it safe to say
T_i = (- m_{ice}L_f)/(m_{iron}c_{iron})-T_f
n once again guys thankyou for all your help its hugely appreciated.
thank you, but I am still a bit confused
i didnt incorporate \Delta Q=c_{H_2O}m\Delta T because it doesn't say anything about the water changing temperature. only that it melts, so figure it was only a phase change. if the water only changes phase and remains at zero degrees does that not...
I have exactly the same problem
is it possible to incorporate equation Q=mLf?
c1m1(Tf-Ti)=m2Lf
if so how would this be rearranged? would this be correct
Ti=((m2Lf)/(c1/m1))-Tf
so confused will appreciate any help at all
Hey guys, had the same problem.
Remember V is a vector quantity so if the pucks are heading toward each other one will be a negative quantity.
eg: (.16x18)+(.16x-12)=(.16x2)+(.16xV2)
so the answer is 4 not 28
Momentum Conservation
.96=.96