Recent content by dickcruz

This can't be the solution I'm only in the twelfth grade

yeah, it's the right question

We haven't covered that kinda integration . I need a substitution type result

You get stuck after a while

You don't have to memorize the identitites. I derive them when i need them the basic ones are Sin^2 x + cos^2 x= 1 Cos2x = Cos^2 - sin^2x sin 2 x = 2. cosx. sinx from the first one we can divide throught by cos and get values for tan^2x +1=sec^x. dividing by sin gives 1+cot^2x...

I do, but there should also be a way to integrate by substitution ive tried a lot but it doesn't seem to be happening

Integrte indefinately (Cos2x)^1/2 ------------- . dx Sin^2 x

The easiest way to go about this is sec^4 (5x) dx let 5x = y (which you can differentialte and substitue accordingly). so let's integrate I= sec^4 x dx. = (sec^2x . sec^2x) dx = ((1+tan^2x) .sec^2x)dx = Sec^2 dx + sec^2x.tan^2x dx = tan x + c + J J = sec^2x.tan^2x dx Now...