Recent content by Dielere

Ah, that helps a bit! Friction slows down the skateboard, so the friction force would be .8526-.5308, which is .3218.That force is opposite to the force of the skateboard sliding down. The total, net force is .5308 right? Is it the force of friction the number that needs to go on top for...

Oh yes, I'm sorry I didn't even notice. But yes, I mistyped that. I'm not sure how I would do that...The way that I've thought of is just Fx/Fn. I could use the mass multiplied by 9.76 to find Newtons, but I don't know what I would do with the downward acceleration without having a mass with it...

I didn't calculate it, that was the actual acceleration of the skateboard and rider moving down the ramp

Yeah, I've figured out the calculator stuff. It was just a mistake on my part. So I have no idea where to go from here...I feel like I've got to be missing some part, or is it as simple as just .5208 divided by 9.76?

I was in Radians for that one part, but I used sin of 5 to multiply by gravity in order to find the new normal force that presses on the skateboard at that angle. Without radians its 9.76, so my thinking is that I would use that for normal force. However when I do it out, I feel like I'm missing...

Homework Statement The coefficient of friction is to be found from a skateboard and rider rolling down a ramp, which has an angle of 5 degrees. The skateboard accelerates at .5308 m/s^2. The mass of the rider and skateboard is 91.3 kg, or 895 Newtons. The other data would be gravity...