3x1 + x2 + x3 = 0
6x1 + 2x2 + 2x3 = 0
-9x1 - 3x2 - 3x3 = 0
I'm not sure how to approach this problem. I've rewritten these equations as a matrix
[3 1 1]
[6 2 2]
[-9 -3 -3]
Reduced Echelon from gave me this
[3 1 1]
[0 0 0]
[0 0 0]
Am I approaching this the wrong way...
OK, That's a good first step. I'm still a little confused as to how to apply the addition method.
can I add [x,y,z] + [a,b,c] then get [x+a, y+b, z+c] ? Then what?
Thanks.
1. {[x,y,z] | x,y,z in R, z = 3x+2}.
How do I determine if this subset is a subspace of R3? Am I wrong when I say this set contains the zero vector? If this is the case, then I have to use the addition and multiplication closure methods, right?
Thanks