Recent content by dk_ch

The circuital law helps to determine magnetic field due to current in case of solenoid ,toroid and straight current carrying wire. Why does it fail for circular current loop?

Homework Statement How to calculate the magnetic field at the centre of a circular current (I) loop of radius r using Ampere law Homework Equations B = μ0I/2r The Attempt at a Solution I take circulation along the circular closed path of radius r passing through the center of the loop and...

thanks

thanks

Actually I mean stationary inflection pts where first derivative is zero and in the graph there are two points where dx/dt is zero.. if t =0 then c = v ,at t=0, dx/dt is negative,hence c also. THANKS ALL for help. if f′(x) is zero, the point is a stationary point of...

the plot was x-t . why not v=dx/dt = 0 at inflection pts?

Homework Statement The accompanying graph of position x versus time t represents the motion of a particle. If p and q are both positive constants, the expression that best describes the acceleration a of the particle is Homework Equations (A) a = – - p – - qt (B) a = - –p + qt (C) a = p + qt...

Homework Statement The accompanying graph of position x versus time t represents the motion of a particle. If p and q are both positive constants, the expression that best describes the acceleration  of the particle is Homework Equations (A) a = – - p -– qt (B) a = –p + qt (C) a = p + qt (D)...

So u have reached the same conclusion as I have , Thanks.

I tried but failed to eliminate v1 initial volume to have the required relation. Please give hints if possible.

Is it possible to arrive at the same result without having taken the initial volume as V0? If possible please suggest a way out.

<complete solutions are not allowed -- post content deleted> gneill PF Mentor

your should be 62x29x7.3x(12x2.54)^3 cm3 since 1 ft =12 inch and 1 inch =2.54 cm

for initial vol V0 the initial pressure is P0/2 for final vol 2V0 the final pressure is (4/5)P0 Then temperature change becomes =(11/10)P0V0/R I think it is correct

If we take initial pressure P0 and initial volume as V0 Initial temp = T1 Final Pressure = P0 (remaining constant) final doubled volume =2V0 and final temp = T2 then by ideal gas law for one mole of gas T2-T1=2P0V0/R -P0V0/R=P0V0/R Is this a correct solution? Then what is the...