Recent content by doke

correct sir but i need to reach a specific formula that can calculate the power

as a result so T Nm = 9000Watt * 9.549 / 4000 rpm = 21.48Nm .then ω=60*4000rpm×2π≈418.88rad/s so P=21.48×418.88 P≈8997.8W Am i correct now ?

i dont see any link sir

thanks for reaching dear, so in which way i can get the required motor power

the motor Rpm also can be 200rpm* 10* 2[ which is the pulley ratio ]= 4000rpm

so is finding the Torque will be halpful so i can convert the 2000 rpm to m/s and use t=p/w to find the torque then multiple it by the rpm so i can get the required power.I feel like I'm going in a vicious circle ot that is correct approach

thanks for reaching out : if i use gear ratio 10:1 that means 200rpm*10 which is the ratio so the motor must run at 2000rpm ? am i correct here ? regarding to the power :i think i must use concept of efficiency which is P motor=Ppump/efficiency . is that correct

does efficiency has a role to obtain the required power?

P=TW but in the question he is saying to obtain power again while i have net power so i got confused here. also i have no idea which formula can obtain the rpm also question provides Rpm

Suddenly the question doesn't provide any figuers

Thanks for reaching out ,The Full Question is : You are a mechanical system design engineer of factory you have to design a mechanical system with an electric motor connected to a gearbox which is connected to the belt-pulley system that drives a water pump should run at 200Rpm and 9kw net...

i got confused because if the connections btw the parts