Recent content by DOMINGO79

Wow... Hey, thanks alot, I think I just opened my eyes:bugeye: and understand how to complete the question... If I have anymore Q's, I will let you know, thanks...

16i-20j-5k = i j k = i(4c-5b)-j(3c-5a)+k(3b-4a) 3 4 5 a b c 16i = i(4c-5b) -3(16 = 4c-5b) -48 = -12c + 15b -20j = -j(3c-5a) → 4(20 = 3c-5a) → 80 = 12c – 20a -5k = k(3b-4a) 32 = 15b -20a...

I am having a huge problem trying to answer the following question: Given the position vector r = 3i + 4j + 5k and torque = 16i - 20j - 5k, find the force vector F which will give the correct result, so that torque = r x F Can anyone please help me solve this!:confused:

I am given the information: A water-skier is pulled behind a motorboat with a rope 8m long. As she is approaching a ramp, she pulls herself 2m to the side of the path of the boat. It creates an angle of 14.5 degrees. I am asked: 1.) how much of the tow rope force is in the forward direction...

I am given the information: A water-skier is pulled behind a motorboat with a rope 8m long. As she is approaching a ramp, she pulls herself 2m to the side of the path of the boat. It creates an angle of 14.5 degrees. I am asked: 1.) how much of the tow rope force is in the forward...