Recent content by donniemateno

chestermiller not sure how you got 2.4 as the only information you are given is 240 and 50. so my initial reaction is to divide by 240 / 50

I have been given these questions as homework and completed them , but you enter them on our online homework system to check if they are correct. It doesn't say which one is wrong though and its frustrating as I don't know where I have gone wrong! I know I have one right as it does say 1/2 is...

so divide by my 10.9 / 11 MPa? so I would get a result of 8.18 or 8.2 rounded

so 10.9 * (0.72/0.04) = 19.62 and 10.9 * (0.12/0.04) = 3.27 so the difference between 19.62 - 3.27 = 16.35 so are you saying try 0.5 (180 MPa / 16.35) = 5.5?

Hey thanks for your help. Any idea on the tresca theory question ? am a little stumped. I know you said you are busy but any help would be appreciated

yes and no. we get questions which come up in a test he following week which are the same as the ones given to take home but the numbers are different, it's to teach us the method. so if you can't remember the method then you can't do the question

I have looked at the safety factor again and in my notes it states I need to get principal stresses; SF = yiled stress / difference between principle stresses So I think the number i get to divide 180 MPa should be the different between the 72 mm measurement and 12 mm measurement so 10.9 *...

so should my last part be : tmax = T/(k1bt^2) yes? = 75000 / ( 0.299 * 72 * ( 12^2) =24.19 MPa or 24.2 MPa rounded

the first part of my previous post is to work out stress which i then use to work out the factor of safety. OK let's make this abit simpler how would you work out the Factor of safety with the data you have been given for part b? and which part ? my formula is tmax = T/(k1bt^2) yes? i have T...

so now using your value if i use it to work out my hoop stress i get (0.72*0.04)*10.85 = 195.3N/m^2 i then take my 180 yield stress and divide it by 195.3 = 0.92 which is a fail part 3 of the question i don't see how the formula is wrong? the formula i used is tmax = T/(k1bt^2) where b is...

Watch your units. Some of your units are wrong. Let me show you an example, using correct units. Am = (12 - 4)(72 - 4) = 544 mm^2 tau = T/(2*Am*t) = (75 000 N*mm)/(2*544*4) = 17.23 MPa Try again. Also, what is the general formula for Tresca theory? I thought it was tensile yield strength...

ladies and gents I have been set a question for homework which is one where if you get one part wrong then the rest of your answers are in correct. It is a 3 questions in one question and i have answered 1 and 2 but can't seem to do part 3 the question is A torque T = 75Nm is applied to...

Ive been asked to express answer is n not kn. Thank yu for your help :) sorry I am slow

Would this be 6 N? Seems very low. I thought the answer would be more like 6 Kn based on an example I have worked out gpa

yes 1000mm to a meter 10mm to a cm so my 150 mm and 200mm should be .15 * .2? this times by 0.2 would give me 0.006