Recent content by doppelganger007
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Double Integration to Find Volume
hmm...I may try that if I can't find an alternative, but is there any way to do this problem with a double integration and not a triple integration? because the section I'm working with is strictly double integration- doppelganger007
- Post #3
- Forum: Calculus and Beyond Homework Help
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Double Integration to Find Volume
Homework Statement Find the volume of the region inside the surface z=x^2+y^2 and between z=0 and z=10 Homework Equations x^2+y^2=10 The Attempt at a Solution I know that I have to use some sort of double integration to find this volume, but I'm not really sure where to begin...- doppelganger007
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- Integration Volume
- Replies: 3
- Forum: Calculus and Beyond Homework Help
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Energy flux vector field problem is the isotherms are circles
Homework Statement Suppose that the isotherms in a region are all concentric spheres centered at the origin. Prove that the energy flux vector field points either toward or away from the origin. Homework Equations J = - k (del)T The Attempt at a Solution so I know that -(del)T is...- doppelganger007
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- Circles Energy Field Flux Vector Vector field
- Replies: 1
- Forum: Calculus and Beyond Homework Help
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Prove c(t) is a Straight Line or Point w/ Zero Acceleration
oh. duh! gratzie- doppelganger007
- Post #5
- Forum: Calculus and Beyond Homework Help
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Prove c(t) is a Straight Line or Point w/ Zero Acceleration
oh ok, so if I integrate that again I get that c(t) = Ct + D, which fits the general equation for a line but then, does that also prove that c(t) could just be a single point?- doppelganger007
- Post #3
- Forum: Calculus and Beyond Homework Help
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Prove c(t) is a Straight Line or Point w/ Zero Acceleration
Homework Statement Let c be a path in R^3 with zero acceleration. Prove that c is a straight line or a point. Homework Equations F(c(t)) = ma(t) a(t) = c''(t) The Attempt at a Solution so i know that since the acceleration is zero, the velocity must be constant, and when you...- doppelganger007
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- Acceleration Zero
- Replies: 6
- Forum: Calculus and Beyond Homework Help
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Really easy question about perpendicular lines in 3D?
great! that helps me understand the issue of parameters does my logic look okay too?- doppelganger007
- Post #12
- Forum: Calculus and Beyond Homework Help
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Really easy question about perpendicular lines in 3D?
^^ anyone that can help confirm my work?- doppelganger007
- Post #10
- Forum: Calculus and Beyond Homework Help
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Really easy question about perpendicular lines in 3D?
^^ subquestion assuming I did everything right, do I use a different parameter for my new equation, or do I have to use the same one in order for the two lines to intersect?- doppelganger007
- Post #9
- Forum: Calculus and Beyond Homework Help
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Really easy question about perpendicular lines in 3D?
OK, so I looked ahead in the book and figured out how to solve for the equation of a plane, so using the fact that the line points in the direction of the vector (1, 1, 1) = (A, B, C), the equation of the plane to which that vector is perpendicular would be A(x - x0) + B(y - y0) + C(z - z0) =...- doppelganger007
- Post #8
- Forum: Calculus and Beyond Homework Help
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Really easy question about perpendicular lines in 3D?
does that mean finding an equation for the plane? what you're saying makes sense, but I don't really know anything about finding the equations of planes...- doppelganger007
- Post #7
- Forum: Calculus and Beyond Homework Help
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Really easy question about perpendicular lines in 3D?
oh boy oh boy, i still need help! please!- doppelganger007
- Post #5
- Forum: Calculus and Beyond Homework Help
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Is Cos(pi(2x+1)) the Key to Simplifying the Search for x Values?
is the original supposed to be sec(pi)(2x+1) = 2?- doppelganger007
- Post #2
- Forum: Calculus and Beyond Homework Help
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Really easy question about perpendicular lines in 3D?
OK so I read over the advice you guys gave me and I'm still a little confused, so what I went ahead and figured out was that the equation of a line l(t) = a + tv, where x = x1 + at y = y1 + bt z = z1 + ct and a = (x1, y1, z1) and v = (a, b, c) where the line points in the direction of v...- doppelganger007
- Post #4
- Forum: Calculus and Beyond Homework Help
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Really easy question about perpendicular lines in 3D?
Homework Statement Find the line through (3, 1, -2) that intersects and is perpendicular to the line x = -1 + t, y = -2 + t, z = -1 + t. Homework Equations line l through P (x1, y1, z1) and Q (x2, y2, z2) has the following form x = x1 + (x2 - x1)t y = y1 + (y2 - y1)t z = z1 + (z2 -...- doppelganger007
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- 3d Lines Perpendicular Perpendicular lines
- Replies: 12
- Forum: Calculus and Beyond Homework Help