Recent content by doubleyou

Thank you - I know this already :) . I just wanted to make sure that this is what makes riding a mountainbike with wide tires more exhausting. And obviously it is.

It doesn't really matter what the mass of B is. In my mind, block A would still start moving relatively to B, when the applied force F is bigger than the friction between the two blocks f_friction = mu_s * mass_a * g... independant of the mass of B

Hmm well... if you look at block A alone and consider block B as being a table: Force equilibrium (at max static friction): F - mu_s * m * g = 0. The moment F gets bigger than mu_s * m * g, there is no longer force equilibrium, thus the block A will accelerate relatively to the table (or block...

To me it looks OK yes... It DOES seem a little weird though. Wouldn't you normally just think that the force F applied just has to be smaller than the maximum possible static friction which is f_statis = mu_s * mass_a * g ?

I'm not exactly sure if this is the answer you're looking for, but I'll give it a go anyways. If the force F you exert on A is smaller than the static friction between the two blocks, they will not move relatively to each other. Therefore you can consider the two blocks as being one block...

So I guess it's the same explanation to why it's more exhausting to ride a mountainbike with wide tires; there's more rubber to deform than on the small tires on a city bike for example = more work lost

Hey there I'm wondering why it's remarkably more exhausting to ride a bike with a flat tire, compared to a bike with a hard inflated tire. The friction force "killing my efforts" so to speak, should be the same; the normal force is the same (my mass doesn't change), and the friction...