Recent content by dpjkw

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    Stopping a Flywheel: Calculating Time and Torque | 10ft, 20000lbs, 2rpm - dpjkw

    It is a basically a solid rubber cylinder of more or less uniform density, other than a 12" dia particleboard core. The weight is approximate based on .036 lbs/in^3 + a, little fudge factor.
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    Stopping a Flywheel: Calculating Time and Torque | 10ft, 20000lbs, 2rpm - dpjkw

    I found a simplifed formula Time (s) = Inertia (lb-ft^2) * Delta RPM / (308 * Torque (lb-ft)) Inertia = .5 * Mass (lbs) * radius ^2 (ft) therefor Inertia = .5 * 20000lbs * 5ft ^2 = 250000 lb-ft^2 Convert 9245 in-lb to 770.4 ft-lb Time = 250000 lb-ft^2 * 1.5 rpm / (308 * 770.4...
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    Stopping a Flywheel: Calculating Time and Torque | 10ft, 20000lbs, 2rpm - dpjkw

    I was trying to simplify the question. It is actually a large industrial belt winding machine. The machine winds industrial belting up to 4' wide while an operator inspects it for damage, up to a diameter of 10' (it varies speed based on diameter to maintain a 30-40 fpm liner feed. It...
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    Stopping a Flywheel: Calculating Time and Torque | 10ft, 20000lbs, 2rpm - dpjkw

    I have a question in regards to time it take to stop a flywheel. I have a 10 foot dia x 3 foot thick solid flywheel that weighs approx 20,000 lbs. It is rotating at about 2 rpm I have a electric brake that is rated to apply 9500 in-lb of torque. How long (sec) or how many rads will it...
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