Recent content by Dr4c0

Isn't that considered by the fact that we're taking the friction force in consideration with the angle (cos 12)?

...wow. i feel like a complete moron. thanks rho! ^.^

the sum of all vertical forces = 0. this is because the car is not accelerating up or down. this means the net force is zero vertically. however, the car is accelerating horizontally by going in a circle (centripetal acceleration). that's why the horizontal accelerations and forces equal the...

centrifugal force is force pointing out from the circle. the inertia of the car provides that. it's not a factor. converting all the forces into acceleration won't do anything. i'll just have accelerations in all different directions instead of forces. that won't solve for any of the values...

very, very good! ...but how do i go about splitting normal force and friction force into horizontal and vertical vectors? :confused:

i wish it were that easy. that would be true if the curve was flat, but the curve is banked. the friction force is at an angle.

car moving along a banked curve with friction (solved) first off, thanks to whoever helps me. you're a life saver. i could just copy it from a friend, but i want to be skilled enough for the AP Physics B exam. so yeah... i just want to understand what i have to do. the logic with this is...