Does Lt=2Ls not presume that both conductors are of equal diameter?
Presumably each one individually can be summed to get a value of Lt if varying diameters are used.
Apologies for any misunderstanding on my behalf.
Cheers
Apologies again for the stupid question, using the V=L(dI/dT), would I then multiply this value by the length of the cable in metres? Presuming that the values of a,b and c used in the inductance equation you gave are in metres also?
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