Recent content by dreamer12

I have seen my mistake

What, so we get heavier? Space launches are done at the equator for a saving of 0.5% of the gravity between pole and equator. Probably less than if they picked an arbitrary point like New York that had a mid latitude position. But they can save as much again by launching at night? I'd be in line...

Laziness. It should be distance to the sun + the sun's radius to give our radius about the orbit, but it was close enough for a ball park figure. I'm not going to be out by a massive factor, but saved my 2 mins research. :)

I don't think so. I want to keep it dimensionally correct so I used base SI units. Metres, seconds and kilograms. http://physics.nist.gov/cuu/Units/units.html

Thanks, I think I am not grasping the physics of the situation. Centrifugal force is F=(m*v^2)/r Assuming Earth goes round the sun at 30,000 m/s Distance to sun (not centre of but ball park) is 150,000,000,000 m So for a man with a *mass of 70 kilos I get roughly...

Thank you. My question is more based on location upon the surface. Why during the day when centrifugal force would throw you into the earth, are you not lighter than at night, when on the opposite side of earth, and centrifugal force would be trying to throw you away from the surface?

Ok, seems like a silly question, but this one has been puzzling me. I'm sure there is an easy answer, but it is not an easy thing to google. So imagine swinging a bucket of water round. The water can be inverted, but it stays in the bucket with centrifugal force. And centrifugal force occurs...