Okay, I completely forgot about the cos(180), which would make the force of friction negative. So instead, now i have:
(.4)(3.0 kg)(9.81 m/s^2) X (1.1 m) X (cos(180)), or -12.9492
So I figured that the only factors I need would be the Initial PEg and the final KE, and therefore I have...
[b]1. The problem statement:
The coefficient of friction between the 3.00 kg block and surface in the figure below is 0.400. The system starts from rest. What is the speed of the 5.00 kg ball when it has fallen 1.10 m? The picture "below" depicts the 3.0 kg block on the table, attached to...