Recent content by drewta

(28m/192) L2 resolves out to .58333 when m=4kg and L=1m are inputted. .58333 is the same as my calculations for I. Doesn't look like moment of inertia is the problem. =/ I suppose the book-provided solution could be incorrect...

So, to confirm, the rod does indeed swing upwards, right? Would you mind checking over my calculations for the alternate problem I posted? I can't seem to get the supposed correct answer (according to the book). The problem's in SI units :)

I think it swings upward as per my explanation in my original post; since the spring is already stretched, it'll want to compress, and thus, it'll swing upward. Not sure - the problem just states that it's an 8lb. uniform bar... I dislike imperial units :( If I do my calculations assuming 8...

Homework Statement The 8 lb uniform rod AB shown in the figure rotates in the vertical plane about a pin at C. The spring attached to the rod at D has a spring constant of 1.25 lb/in., and its unstretched length is 24in. If the rod is released from rest in the position shown, determine its...