Recent content by DrIxn
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How Is Torque Calculated on a Current-Carrying Loop in a Magnetic Field?
Yes I already did that, for I2 (higher resistance) I got It(total current)*R1/(R1+R2) And other other current is I1=It-I2 And I calculated the angle between the wire and b field, and the length of the triangular side of the wire and found F1=I1*l*sin(theta)*B and F2=I1*l*sin(theta)*B- DrIxn
- Post #5
- Forum: Introductory Physics Homework Help
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How Is Torque Calculated on a Current-Carrying Loop in a Magnetic Field?
Okay here is a picture of the diagram http://i.imgur.com/LzjNPkV.png the current does not go in a loop and the whole wire has the resistances given- DrIxn
- Post #3
- Forum: Introductory Physics Homework Help
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How Is Torque Calculated on a Current-Carrying Loop in a Magnetic Field?
Homework Statement There is a wire (current I = 1.05 A) that splits into two channels; of resistance R2 = 6.60 and R1 = 1.25 , and re-joins, forming a current in the shape of an isosceles triangle with base distance d = 6.90 cm and height L = 14.0 cm. The loop is entered into the space between...- DrIxn
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- Cylinder Inclined Inclined plane Plane
- Replies: 7
- Forum: Introductory Physics Homework Help
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Torque from straight wire segment
Thanks for your help rude man, I ended up crossing r x dF to get the answer, not dr x F- DrIxn
- Post #6
- Forum: Introductory Physics Homework Help
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Torque from straight wire segment
I tried it your way(dont know how to make the vectors bold): tan(theta)=dy/dx I used dl= dx i + tan(theta) dx j So when I took the cross product i got dF=-(I*B0*tan(theta)/(4*L^3))*x^3 dx i + (I*B0/(4*L^3))*x^3 dx j And Integrated that from 0 to L*cos(theta) so F=...- DrIxn
- Post #3
- Forum: Introductory Physics Homework Help
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Torque from straight wire segment
Homework Statement A straight wire segment of length L makes an angle of 21.0 degrees with respect to the x axis. The wire carries a current of 4.10 A in the direction shown in the figure. There is a magnetic field in the vicinity of the wire which points in the negative z direction with a...- DrIxn
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- Torque Wire
- Replies: 6
- Forum: Introductory Physics Homework Help
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How Does Resistivity Vary in a Conical Material with Changing Dimensions?
Okay so the cross sectional area would be a circle, A=pi*r^2 , and since r varies linearly with the length of the cone A=pi*x^2 And integrating with respect to x.. (6/pi*10^6)*x^2 dx from xi to xf?- DrIxn
- Post #5
- Forum: Introductory Physics Homework Help
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How Does Resistivity Vary in a Conical Material with Changing Dimensions?
Would it be something else? A bunch of little rings expanding out would make a circle yes?- DrIxn
- Post #3
- Forum: Introductory Physics Homework Help
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How Does Resistivity Vary in a Conical Material with Changing Dimensions?
Homework Statement A piece of conically-shaped material is placed in a circuit along the x-axis. The resistivity of this material varies as rho=(6*10^6)*x^4 (where x is measured in meters and rho is measured in ohm*meters), and its radius varies linearly as a function of x, ranging from...- DrIxn
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- Cone Resistance Section
- Replies: 5
- Forum: Introductory Physics Homework Help
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How Does Flipping a Capacitor Affect Charge and Capacitance in a Circuit?
Ah, thank you again :) I thought I had tried that answer already- DrIxn
- Post #3
- Forum: Introductory Physics Homework Help
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How Does Flipping a Capacitor Affect Charge and Capacitance in a Circuit?
Homework Statement So 4 capacitors are hooked up as shown in the picture on the left http://i.imgur.com/RiNcYz4.png each with C=0.8 F and the voltage from the battery V=16.6 V Then they are disconnected and hooked up as shown on the left with one capacitor flipped. What is the effective...- DrIxn
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- Capacitors
- Replies: 2
- Forum: Introductory Physics Homework Help
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Energy Dissipation in a Time-Dependent Current Circuit
Ah, yes thank you I got it. I was over complicating it I guess- DrIxn
- Post #3
- Forum: Introductory Physics Homework Help
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Energy Dissipation in a Time-Dependent Current Circuit
Homework Statement The current in amps through a resistor with a resistance of 90 Ohm varies according to I=2.8e^(−7.6t) when t is in seconds. What is the total energy dissipated in the resistor from 0.5 to 1.4 seconds, written in Joules? Homework Equations I(t)=dQ/dt dU=dQ*dV...- DrIxn
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- Current Time Time dependent
- Replies: 11
- Forum: Introductory Physics Homework Help