I just tried to solve for (a) and I got 41.53 degrees, do you know if this is right?
Thanks for all of the help, I have to go to school now. Thanks again.
1) It's centripetal acceleration is 20.83^2/50= 8.68 m/s^2
2) The forces acting on it are gravity, the normal force (perpendicular to the incline), and friction (down the incline)
so Fnx+Fsx=ma
Fn*(Sin theta)+.45*Fn*Cos (theta)= 11284.72
This is where I get stuck, I was taught to use...
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