Recent content by Dulcis21

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    Kinetic Energy of gas Molecules

    Oh I figured it out lol, it needed (5/2)kT to work and then multiply by Avogadro's number.
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    Kinetic Energy of gas Molecules

    I thought my method was right but my homework web-assign isn't accepting that answer :( It asked for it in 2 sig figs so i put it in as 3.8 *10^3 but it still said no...
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    Kinetic Energy of gas Molecules

    Hi, the question, I'm having problems with is this: A 1.0 mol sample of hydrogen gas has a temperature of 30 C. What is the total kinetic energy of all the gas molecules in the sample? How fast would a 75 kg person have to run to have the same kinetic energy? Relevant equations: K = (3/2)kT...
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