Recent content by Dynamo

Thanks for having a look. Thats pretty much what I get.. From: \frac{dT}{dt} = \frac{Q}{MC} - \frac{1}{RMC} (T- \theta) I then diff with respect to theta, and get what you get, I can't understand how he, and I quote... "This equation can be solved for the change in temperature...

Hi all. I am doing some work with temperature equations. I have a book that gives an equation and then manipulates it. However, I can not follow what the author does, so can anyone help: He starts with: [FONT=Courier New]dT/dt = Q/MC - (T-O)/RMC (in the following I use the text...