Recent content by ebk11

Okay, so I got du = 1/xdx, and v = x^3/3 Then, I did: lnx * x^3/3 - [integral]x^3/3 * 1/xdx then: lnx * 1/3*x^3 - 1/3[integral]x^3/xdx which simplifies to: lnx * 1/3 * x^3 - 1/3[integral]x^2dx which is: lnx * 1/3 * x^3 - 1/3[integral]x^3/3 + C final answer: ln(x) * 1/3 * x^3 - 1/9...

Well that's what I was confused about. When you are setting up a substitution by parts problem...when you get u, you differentiate to get the du...and then you integrate to get v from dv, right? So it should be x^3/3, not 2x?

Homework Statement Evaluate the following integral: [integral](x^2)*ln(x)dx Homework Equations I believe this is substitution by parts... The Attempt at a Solution I chose u = ln(x), and dv = x^2. The problem I am having is I can't figure out what du and v should be, because I am...