Actually, on relativistic mass you can think of it this way:
The total energy of a point mass in motion can be given by the formula:
E = T + mc**2
In case u <<c , E = 1/2 * mu**2 + mc**2 (1)
T_cl = 1/2 * mu**2
while,
when u->c, E = (γ-1)*mc**2 + mc**2 (2)
T_rel =...
Totally agree with Choppy, as I happen to belong in the latter category. Do your PhD, but even so, you have a couple of semesters to go.
Have you ever taught (even informally)?
Have you considered the possibility that if you start teaching before doing your PhD, the timescales will be really...
You can also find many ICT-based educational resources and participate in relevant communities here: www.inspiringscience.eu
as well as here: portal.opendiscoveryspace.eu
This means for example that we cannot observe Raman scattering (which has negligible yet not zero cross section) from the 10.3 eV photons when we shoot them at hydrogen?
Agreed, but in the case between the fundamental and the first excited state we are not (yet) in the high quantum numbers realm.
In this part, the energy difference between the different states is of order 0.1 eV or less, whereas here we are dealing with ~1 eV differences.
The conservation of...
Yes, but here we don't speak of energies greater than the ionisation energy
You say:
-----------------------------------------------------------------------
For the simple case of an atom in a gas, the well known rules of QM apply (as in the hydrogen atom we all know and love). A very high...
So , sophiecentaur what you suggest is that if we bombard a hydrogen atom in its ground state with 10.3 eV photons, it will not absorb them (and thus be excited) , because they don't have the correct energy (10.2 eV sharp) to jump to the first excited state?
As an addition to ZapperZ's answer, this QED process is called Delbruck scattering . Photon's spontaneously create virtual electron-positron pairs which interact.
This is actually one of the most prominent mechanisms of gamma ray attenuation in high energy astrophysics.
I think that the extra energy goes to the whole atom:
If (e,g) you have a hydrogen atom with an electron in the ground state n=1 (E1=-13.6 eV), then to take it to the first excited state n=2 (E2 = -3.4 eV), you need to provide it with 10.2 eV of energy. To take it to the third from the second...
Good afternoon from Greece!
First of all, I want to congratulate you on following your passion in life. It is not an easy decision to drop out from school for pursuing your dream, and once you realize it didn't fulfill your expectations , start all over.
If you have such a drive for science...
Good afternoon,
I am trying to simulate the propagation of electrons in copper. To do so, I fill a Landau distribution with mean the most probable value of energy loss. However, my formula doesn't seem to work as I find that I can have higher energy loss than the electron energy itself!
Could...
Hello, I am interested in computing the optimal depth of a copper absorber for Sr-90 decay electrons.
I want to find a way to simulate a beta decay spectrum in C++.
Have you got any idea or possible documentation on where I could start??
Thank you!
Hello there,
there is a nice book speaking of the tests conducted on the hypothesis of a fifth force.
https://www.amazon.com/dp/1563961199/?tag=pfamazon01-20
There is research going on on some new experiments (At JLab and GSI), where they try to detect some new gauge bosons A' (popularly named...
It is not necessarily *only* photoelectric effect that takes place there.
It could be successive compton scattering with all the energy absorbed within the detector, taken that the detector is thick enough.
A 10% effect is an order of magnitude difference in counts and thus in the cross...