I knew it had to do with sampling, so I just took 4 from 5.5 and got 1.5 on the http://www.cs.washington.edu/homes/jrl/normal_cdf.pdf here and that's how I got it, I think that's more than likely completely incorrect.
P(M>4), that's what I thought you did. Am i way off?
Thank you very much, your too good.
Sorry about the question marks.
Can I ask you one more thing
What would be the probability of drawing 30 tiles and obtaining a meal tile number of less than 4?
I keep getting .9332 by using the tables of the normal distribution, I know that's probably...
Homework Statement
If you have a box of 1,000 items, with numbers 1-10 on them, 100 for each!
And this proves the discrete uniform probability distribution.
1/10 for each.Homework Equations
Mean = u = Exp(x) = e(x)
St dev worked out by the variation.
St Dev = square root of the variation...
I found the x and y mean...
u=Ep(x)x
ux=(10)(0.1)+(14)(0.5)+)(16)(0.4) = 14.4 -> mean for X by using the marginals
uy= same procedure I got 21.61.
Do you know how you get the median for this, if you understand what I mean?
Well see the table looks a bit odd there Y is along the top and X is along the left hand side.
9,15 and 30 are belong to Y and 10,14 and 16 are belong to X. then the numbers are in the table.
It says find the means, medians and st devs of X and Y.
I did what you said before I posted here, but...
Joint Distribution (Means,Medians...) PLEASE HELP!
Hi, I'm wondering if somebody could help me understand this...
If you have a joint distribution with
Hourly Wage (Y)
Years of Education (X) 9 15 30
10 0.07 0.02 0.01
14...