okay so if I do that then I it is (6M/1L)(20ml/1000L)= .12 moles
What I was thinking though is then why do they have us weigh the full cylinder and then the empty cylinder? because then I get 20.586 g of HCl used and I am not really sure where that is coming into play? My other thought was...
okay here are the questions so you see what I need:
1. Clearly show the following calculation of the experimental molar mass of the alkali metal from the recorded data of one of your trials. Identify all numbers and units.
a. Find the mass of CO2 released.
b. Find the number of moles of CO2...
how do I get a fully balanced equation if I don't know one of the elements? as a matter of fact the last question is "Using your identification of the metal write a balanced equation for the reaction that occurs ..."
I am beginner chem student and I am lost with mass loss. We did an experiment in lab where we are trying to identify a mystery metal. let me describe. We weighed our flask, then weighed our flask with about 1.5g of the mystery metal. Then we added 20ml of 6M HCl to a graduated cylinder and...