Recent content by EdisT

Would it then just be the integral from a to infinity of H(x-a)e^{-bx-i \omega x} dx or the integral from a to infinity of e^{-bx-i \omega x} ?

Homework Statement Find the Fourier transform of H(x-a)e^{-bx}, where H(x) is the Heaviside function. Homework Equations \mathcal{F}[f(t)]=\frac{1}{2 \pi} \int_{- \infty}^{\infty} f(t) \cdot e^{-i \omega t} dt Convolution theory equations that might be relevant: \mathcal{F}[f(t) \cdot...

I ended up plotting in Mathematica after starting from MATLAB (which didn't work because it approximates infinity at around 7E96 I think, and even when I divided it by 1E96 it would first calculate the factorial, approximate it to infinity, then say infinity divided by a large-ish number is...

Ah thank you!

Hey, I'm unsure why the following returns an error: Any ideas on how to fix this?

Hey so I'm working on a simulation to compute the multiplicity of two Einstein solids.. long story short I'm having a tough time plotting a function. To start, I defined the following: Which, when simplified yields: I named this simplified result K: Plotting this... What I get is...

Of course, the integral becomes x^4+3x^4 dx. thank you!

dr = (i + 3x2) dx The dot product would be v⋅dr = xy+3x4 dx The integral would then be: ## \int_{-1}^2 xy+3x^4 \, dx ## ?

x would be the independent variable, so it would be x^3j?

r=x^3i+yj ?

It's been a while... I don't quite remember

No I have no idea how to split it up, the dot product should be easy enough but I'm more used to x(t), y(t) being given.. How would you split it up?

I'm used to parameterizing however I'm not sure how to solve these types of problems, any help would be much appreciated. 1) Calculate the line integral ∫v⋅dr along the curve y=x3 in the xy-plane when -1≤x≤2 and v=xyi+x2j 2) a) Find the work that the force F = (y2+5)i+(2xy-8)j carries...

one of the observers is relatively stationary, does that mean that for one of the calculations, v=0?

Ah my bad, but if the rest is correct then I would like to thank you very much!