Recent content by ejezisek

Some updates I've made regarding the work to part 3. Due to conservation of energy, the velocity of particle 1 - change in velocity = velocity of particle 2 + change in velocity of particle 1 * m2/m1

Homework Statement From a large distance away, a particle of mass m1 and positive charge q1 is fired at speed v in the positive x direction straight toward a second particle, originally stationary but free to move, with mass m2 and positive charge q2. Both particles are constrained to move...

I GOT IT! Thanks for helping :)

m=2 Kinetic Energy=1/2 m * v^2=v^2=10100^2=(1.01*10^4)^2=1.02*10^8 Potential Energy=-GMem/r=-6.673*10^-11*5.97*10^24*2/6.38*10^6=-10^7*6.673*5.97*2/6.38=-12.5*10^7=-1.25*10^8 Total Energy=-2.3*10^7 Potential Energy*earthRadius/-2.3*10^7=radius...

I'm sure I messed up somehow i got 1.73*10^7m and well... that can't be the answer.

i chose m=2 because i have to divide by two in the kinetic energy equation. kinetic energy:102010000 total energy: -22998502 PE:-125008502

i can pretend the object has any mass i want. the initial energy is 102010000 for an object with m=2kg. The initial potential energy would be 0 I believe.

1/2 m * v * v I'm trying to do what ehild said above use potential and kinetic energy. I guess i probably don't need to know m. Ill just try using m as 2 for both potential and kinetic.

how do i calculate kinetic energy without knowing the mass of the object?

How is it that i calculate the final energy?

At the Earth's surface a projectile is launched straight up at a speed of 10.0 km/s. To what height will it rise? Ignore air resistance and the rotation of the Earth. 2.52 * 10^7 is the answer.

Me=Mass of the earth m=mass of object away from the Earth which we don't know. r= the distance halfway between the middle of the Earth and the middle of the object. G= gravitational constant 6.673* 10^-11. U(r)=-G*Me*m/r Thank you very much for trying/helping me out :) If it would help you out...

I am not entirely sure on how to do that. Could you please explain?

I thought I might be able to find the average gravitational force used in the equation. And use that for g. Is this wrong? The main thing I am looking for is additional formulae I may be missing.

Homework Statement An object is launched at a speed of 10.1km/s. What is the maximum height of this object. The answer is within 10% of 2.88x10^7. and should be relatively close to it. Homework Equations radius of earth=re. I believe 9.8*((re)/re+h)^2=gravity is relevant. a=g...