Recent content by elflacodepr
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Square Root Method - Fractions
Homework Statement x^2 - 1/2x - 3/16 = 0 The Attempt at a Solution Actually, I don't know where to start since I have fractions.- elflacodepr
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- Fractions Method Root Square Square root
- Replies: 1
- Forum: Precalculus Mathematics Homework Help
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Solve Square Root Method: (x-1)^2 = 4
Thanks!- elflacodepr
- Post #5
- Forum: Precalculus Mathematics Homework Help
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Solve Square Root Method: (x-1)^2 = 4
Thanks, All I did now is use the square root right on start: √(x - 1)^2 = √4 So now we go this: x - 1 = ±2 which gives me the following results: x - 1 = ±2 x = 2 + 1 x = 3 OR x - 1 = ±2 x = -2 + 1 x = -1- elflacodepr
- Post #3
- Forum: Precalculus Mathematics Homework Help
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Solve Square Root Method: (x-1)^2 = 4
Homework Statement (x - 1)^2 = 4 The Attempt at a Solution This is what I've done (x - 1)^2 = 4 Everything inside parenthesis goes to: ^2 x^2 - 1^2 = 4 now we got x^2 - 1 = 4 Now (I think) I use the square root method x^2 - 1 = √4 x^2 - 1 = 2 Now I factorize: (x - 1) (x +1) = 2 This is...- elflacodepr
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- Method Root Square Square root
- Replies: 4
- Forum: Precalculus Mathematics Homework Help
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How Do You Solve Equations with Parentheses and Negative Signs?
Yes that helped! This is what I did: 8x - (3x + 2) = 2x - 10 8x - 1(3x + 2) = 1(2x - 10) 8x - 3x -2 = 2x - 10 (Now I move all variables together) 8x - 3x -2x = -2 - 10 3x = -12 3x/3 = -12/3 (3's are canceled) x = -4 Thanks a lot! I forgot I could multiply by 1 so the exercise didn't...- elflacodepr
- Post #3
- Forum: Precalculus Mathematics Homework Help
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How Do You Solve Equations with Parentheses and Negative Signs?
Homework Statement I want to solve this equation: 8x - (3x + 2) = 2x - 10 2. The attempt at a solution I tried this: 8x - (3x + 2) = 2x - 10 (3x + 2) = 2x - 8x -10 (3x + 2) = -6x - 10 I know how to break parenthesis when there are no signs between a number and the...- elflacodepr
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- Break
- Replies: 4
- Forum: Precalculus Mathematics Homework Help