Thanks, All I did now is use the square root right on start:
√(x - 1)^2 = √4
So now we go this:
x - 1 = ±2
which gives me the following results:
x - 1 = ±2
x = 2 + 1
x = 3
OR
x - 1 = ±2
x = -2 + 1
x = -1
Homework Statement
(x - 1)^2 = 4
The Attempt at a Solution
This is what I've done
(x - 1)^2 = 4
Everything inside parenthesis goes to: ^2
x^2 - 1^2 = 4
now we got
x^2 - 1 = 4
Now (I think) I use the square root method
x^2 - 1 = √4
x^2 - 1 = 2
Now I factorize:
(x - 1) (x +1) = 2
This is...
Yes that helped! This is what I did:
8x - (3x + 2) = 2x - 10
8x - 1(3x + 2) = 1(2x - 10)
8x - 3x -2 = 2x - 10
(Now I move all variables together)
8x - 3x -2x = -2 - 10
3x = -12
3x/3 = -12/3
(3's are canceled)
x = -4
Thanks alot! I forgot I could multiply by 1 so the exercise didn't...
Homework Statement
I want to solve this equation: 8x - (3x + 2) = 2x - 10
2. The attempt at a solution
I tried this:
8x - (3x + 2) = 2x - 10
(3x + 2) = 2x - 8x -10
(3x + 2) = -6x - 10
I know how to break parenthesis when there are no signs between a number and the...