Recent content by ellatha

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    Circuit Problem -- Two voltage sources and some resistors

    85% on the first exam; thanks for the help!
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    Magnetism Wire Loop: Solve Problem in 1.5 Hours

    Okay guys I have an hour and thirty minutes before my exam; I know how to do the top problem; just use the formula B = mew x current/(2 x pi x r) then add the magnetic fields and use the right-hand rule to get direction, but I'm stuck on the bottom one.
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    Circuit Problem -- Two voltage sources and some resistors

    I don't think this kind of problem will be on my exam tomorrow (there will only be 6 problems; 4 from 4 chapters and 2 from 1 chapter), but we did go over the material. The only thing that confused me about these KCL problems is when to add or subtract when tracing the paths of the current. I...
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    Circuit Problem -- Two voltage sources and some resistors

    Okay, so like in this circuit: The voltage sources are parallel and there are three possible circuit paths so we would have to use Kirchhoff's Rules to determine the the value of the currents and it would be a much more difficult problem, correct?
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    Circuit Problem -- Two voltage sources and some resistors

    It would be 3.0 V total. But what if the batteries were oriented such that the + end of one faced the + end of the other? Also, does it make a difference if they're parallel rather than in a series? Yes; Vtotal = 30V, and Rtotal = 18 Ohms, so I = 1.67 Amps. The voltage drop across the 10 Ohm...
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    Circuit Problem -- Two voltage sources and some resistors

    My professor e-mailed us yesterday and said that that the "top left" is A and the "top right" is B. So I'm guessing Vb - Va is supposed to be the voltage drop across the 10 Ohm resistor? I know how to add resistors and capacitors, but I do not know how to add voltage sources. Can you please...
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    Circuit Problem -- Two voltage sources and some resistors

    Let's say I start at the high voltage part of the Emf source on the right and go counter-clockwise; the first thing I hit is the 10 Ohm resistor, and the current would not split up the junction because the wire is open-ended, correct? So the next thing I would hit is the 8 Ohm resistor, then the...
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