ok than you get a result in Joules and Joule is Newton*meter so you divide the work by the g force?? or what.
I still don't completely understand this theta part. If theta eaquals 2*Pi for one wheel turn than you get the result W=24Pi Joules and if you divide it by gravity force you get a...
had an epiffany (let's say I spelled that correctly). You divide torque (48Nm) by radius (0.21m) and get braking force, that divide that by mass and get braking acceleration.
Than easily length. s=v^2/(T/(m*a))
and for the coefficient you divide braking force by gravity force and get 0,19...
I see what you are aiming to but can not figure out how many times does it turn or for how many radians does it turn.
Is there no way I can use the standard torque equation or a static fraction force equation?
I also found this equation but i don't know how to use it because I am not looking for the value of Work or do not have any other value for theta that 90degrees which is the angle between the surface and the force in the equation
F(sf)=c(sf)*Fn
where Fsf is force of static friction; c(sf)...
well because it depends on the velocity in in the equation we have Wk =(m*v^2)/2. So when the car brakes it lowers down and when it stops it is equal to zero.
It is my rookie year on the university so we are not supposed to solve it with kinetic energy.
Yes of course braking my bad. :)
Homework Statement
We have a car with mass of 1200kg driving at 55km/h. It suddenly starts breaking. The breaks "work" on every of the 4 wheels with the constant torque of 12Nm. The radius of the wheels is 0,21m.
Question 1: How long does the car travel before it stops if the wheels have...