Recent content by eme_girl

Prove that for any vectors a and b, |a-b| is less than or equal to |a| + |b| I'm kind of lost, b/c i can't see a case where |a-b| would actually result in a value being less than |a| + |b|. I've tried doing a proof that is similar, and when I was taught, the definition of absolute value...

How do you find the angle between the co-ordinate axis (i.e. the xz plane) and another plane in general?

You have to assume the statement to be proved is false and then work towards a contradiction.

I understand what you just found. But no, I do not know how to find a vector's that perpendicular to both those vectors.

Find the scalar eq'n of a plane that is perpendicular to the plane with normal vector [3,1,2] and passes through points A(2,-6,-1) and B(1,2,-4). I think that the normal vector can be the direction vector of this new plane. But then, in order to find the scalar eq'n I need a normal vector...