Recent content by emma402

  1. E

    Ball Velocity at Different Times

    or did we answer (a) and I am not aware of it?
  2. E

    Ball Velocity at Different Times

    i'm still wondering about the velocity for (a)...i feel like we were getting close and stopped working on that. can we work on that and then work on (c)? for (a) is it v=20m/s??..that is what it comes out to be with the v=40m/s + (-10m/s^2)(2s) and for (c) do I use the displacement...
  3. E

    Velocity and acceleration of a ball

    just so there's no more confusion, the answer for b is the previous graph on the left...meaning the graph that curves IN when looking from the graph out b.c the graph on the left has a less steep slope than the one on the right. am I correct?
  4. E

    Ball Velocity at Different Times

    that is v=20m/s that is 4, but what is that the answer to? the t in the displacement equation?
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    Velocity and acceleration of a ball

    sorry, I was looking at it from curve compared to the atmosphere...the one on the left would have the decreasing acceleration?
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    Velocity and acceleration of a ball

    that it is a large slope or hill soooo it would be the hill curving out?
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    Ball Velocity at Different Times

    you get 30m/s^2 right? i took v=40m/s + (10m/s^2)(2s)=60m/s "v=40m/s + (-10m/s^2)t and we want to find t when v=0. That is 0=40 + (-10m/s^2)t and solve for t. What do you get?"...i have no clue on the algebra on this!
  8. E

    Velocity and acceleration of a ball

    the one on the left...i take it you are leading up to the point of the shapes of the hills?
  9. E

    Ball Velocity at Different Times

    when t=0? is (a) v= 60m/s?..b.c 2sec is still going up?
  10. E

    Ball Velocity at Different Times

    for (b) I now have a -70m/s for that velocity...i just wanted to see if that was right?
  11. E

    Velocity and acceleration of a ball

    it is going down a hill...
  12. E

    Ball Velocity at Different Times

    ooo that means a= -10m/s^2? after 2 sec. it would be a pos. 10m/s^2...after 11 sec that value would change to -10m/s^2 correct?
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    Ball Velocity at Different Times

    ok so i think I'm solving for displacement then?...which would be the ave.velocity multiplied by time...and the ave velocity is 1/2(Vo + v)...so 1/2(40m/s + 60m/s)= 50m/s...if that is the ave. velocity then 50m/s(2s?) I'm confused on which time it wants...
  14. E

    Ball Velocity at Different Times

    i don';t understand how my vaules are wrong? the math is done right isn't it? when you throw the ball up the velocity is going down or slowing down until it reaches 0 at the turning point. the value of A=10m/s^2...(this is what we are using other than 9.8m/s) if the value is pos it is going...
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