Recent content by emma402
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Ball Velocity at Different Times
or did we answer (a) and I am not aware of it?- emma402
- Post #27
- Forum: Introductory Physics Homework Help
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Ball Velocity at Different Times
i'm still wondering about the velocity for (a)...i feel like we were getting close and stopped working on that. can we work on that and then work on (c)? for (a) is it v=20m/s??..that is what it comes out to be with the v=40m/s + (-10m/s^2)(2s) and for (c) do I use the displacement...- emma402
- Post #26
- Forum: Introductory Physics Homework Help
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Velocity and acceleration of a ball
just so there's no more confusion, the answer for b is the previous graph on the left...meaning the graph that curves IN when looking from the graph out b.c the graph on the left has a less steep slope than the one on the right. am I correct?- emma402
- Post #28
- Forum: Introductory Physics Homework Help
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Ball Velocity at Different Times
that is v=20m/s that is 4, but what is that the answer to? the t in the displacement equation?- emma402
- Post #24
- Forum: Introductory Physics Homework Help
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Velocity and acceleration of a ball
sorry, I was looking at it from curve compared to the atmosphere...the one on the left would have the decreasing acceleration?- emma402
- Post #26
- Forum: Introductory Physics Homework Help
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Velocity and acceleration of a ball
that it is a large slope or hill soooo it would be the hill curving out?- emma402
- Post #24
- Forum: Introductory Physics Homework Help
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Ball Velocity at Different Times
you get 30m/s^2 right? i took v=40m/s + (10m/s^2)(2s)=60m/s "v=40m/s + (-10m/s^2)t and we want to find t when v=0. That is 0=40 + (-10m/s^2)t and solve for t. What do you get?"...i have no clue on the algebra on this!- emma402
- Post #22
- Forum: Introductory Physics Homework Help
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Velocity and acceleration of a ball
the one on the left...i take it you are leading up to the point of the shapes of the hills?- emma402
- Post #22
- Forum: Introductory Physics Homework Help
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Ball Velocity at Different Times
when t=0? is (a) v= 60m/s?..b.c 2sec is still going up?- emma402
- Post #20
- Forum: Introductory Physics Homework Help
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Ball Velocity at Different Times
for (b) I now have a -70m/s for that velocity...i just wanted to see if that was right?- emma402
- Post #17
- Forum: Introductory Physics Homework Help
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Velocity and acceleration of a ball
it is going down a hill...- emma402
- Post #20
- Forum: Introductory Physics Homework Help
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Ball Velocity at Different Times
ooo that means a= -10m/s^2? after 2 sec. it would be a pos. 10m/s^2...after 11 sec that value would change to -10m/s^2 correct?- emma402
- Post #16
- Forum: Introductory Physics Homework Help
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Ball Velocity at Different Times
ok so i think I'm solving for displacement then?...which would be the ave.velocity multiplied by time...and the ave velocity is 1/2(Vo + v)...so 1/2(40m/s + 60m/s)= 50m/s...if that is the ave. velocity then 50m/s(2s?) I'm confused on which time it wants...- emma402
- Post #15
- Forum: Introductory Physics Homework Help
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Ball Velocity at Different Times
i don';t understand how my vaules are wrong? the math is done right isn't it? when you throw the ball up the velocity is going down or slowing down until it reaches 0 at the turning point. the value of A=10m/s^2...(this is what we are using other than 9.8m/s) if the value is pos it is going...- emma402
- Post #13
- Forum: Introductory Physics Homework Help
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Acceleration: is this accelerating?
great, thanks!- emma402
- Post #5
- Forum: Advanced Physics Homework Help