Recent content by emoseman

Do you know of a good source on the topic of Free Body Diagrams? A book perhaps that teaches this in detail? Or maybe even a reference on the internet? Thanks very much for all of your help, I really do appreciate it! -- Evan

I've never seen this solved that way, but it makes more sense. I've been taught to create a table containing the x and y forces and then solve for T, in this case I thought it would be T = Fcos theta. Which is obviously wrong. It turns out to be T = F * (inverse sin) theta Have I been taught...

Why is it Hypotenuse over adjacent and not adjacent over hypotenuse? I thought that cosine = adjacent / hypotenuse?

Homework Statement A dirigible is moored to two wires. The hydrogen capacity of the craft was 200,000 m3, and together with its cabin, access spaces, and navigation surfaces it displaced 205,000 m3 of air. Its fully-loaded weight, including hydrogen gas, engines, diesel fuel, crew, 72...

Wow I think I finally am starting to see it. I'm not sure why this of all things this is giving me the most difficulty. So in using the method of getting the proper distance from a perpendicular line from the wire I can see now how to construct the triangle. And, I would use cosine to find...

This brings up my next question which is in regards to the free body diagram for the other side of this bar which is the wire attached to the rod at 110 degrees. The method of splitting up the force into its x and y-axis components makes sense and does provide extra equations when trying to...

Okay I think I see it now, thanks!

Sorry for being elementary with this, but this is a fundamental concept I'm trying to understand better because it is causing me a lot of headaches. The position vector d is the bar coming off the right of the pivot point and at the end hangs the weight. And the force vector mg is the weight...

Thank you very much for your reply. The first method you document is using the cross-product of the two vectors, which I understand. But, where does the 120 degrees come from in "mg(.40)(sin 120)"? Thanks again! -- Evan

I was going to start with the 3.0Kg weight at the end of the bar. The image shows that it is 60 degrees less than the horizontal plane of the bar. But, what doesn't make sense, is what is that in relation to? The weight is acting vertically, but it is hanging off the end of the bar at 60...

Homework Statement http://img384.imageshack.us/img384/2760/picture1uw7.png http://g.imageshack.us/img384/picture1uw7.png/1/ I'm trying to setup a free body diagram for this problem, and I'm not even sure where to start with the angles. That is basically my question, when do I use cos and...

Nevermind, it is the downward force due to gravity that is causing a torque force rotating about the axis denoted by L. Just tired this afternoon... :)

I'm trying to solve a similar problem using this example, but I'm confused as to where the 4 comes from in the first equation: Sum(T_z) [pivot at L] = 2 F_r - 4 mg = 0