Recent content by Enovik

  1. Enovik

    I Twin Paradox - difference between outbound and inbound

    OK. And Lorentz transform will give the speeding-up of the time ##t'##. Is that so? And there is the derivation for the appropriate formulas?
  2. Enovik

    I Twin Paradox - difference between outbound and inbound

    Relativity acts on frames only? OK! Let's navigate and calculate in one stationary frame and our watches and sizes still invariable at any speed. Is that so?
  3. Enovik

    I Twin Paradox - difference between outbound and inbound

    Lorentz formulas are one way ticket? What will you say travelling twin on the back way? What will show his watch?
  4. Enovik

    I Twin Paradox - difference between outbound and inbound

    2. v is the velocity of the moving away along axis x. The moving away in -x direction is not a new scenario.
  5. Enovik

    I Twin Paradox - difference between outbound and inbound

    Thank you. It is the expecting answer. Some more questions, please. How to use Lorentz transforms if frames are approaching along the axis x? Is it needed to use v<0 in Lorentz transforms, or v>0 at any rate? And did you saw Lorentz formulas derivation for the approaching frames?
  6. Enovik

    I Twin Paradox - difference between outbound and inbound

    I do not deny relativity. I want to know what is the sense of the symbol v in Lorentz formulas. Is it possible to choice true answer from the next? 1. v is the module of vector speed, which can be directed in any direction. 2. v is the velocity of the moving away along axis x. 3. v is any...
  7. Enovik

    I Twin Paradox - difference between outbound and inbound

    The conditions x=ct and x'=ct' are used in any Lorentz formulas derivation. This conditions are consequences from the second STR postulate.
  8. Enovik

    I Twin Paradox - difference between outbound and inbound

    Oh yes. It is not possible to understand, it is possible to believe only.
  9. Enovik

    I Twin Paradox - difference between outbound and inbound

    Lorentz formula $$t' =\frac{t-vx/c^2}{\sqrt{1-v^2/c^2}} = t\sqrt{\frac{1-v/c}{1+v/c}}$$ if x=ct. And equalities x=ct and x'=ct' are the base conditions for Lorentz formula derivation. So, equation $$t' =t\sqrt{\frac{1-v/c}{1+v/c}}$$ is quite right Lorentz formula, Value t' is the time in the...
  10. Enovik

    I Twin Paradox - difference between outbound and inbound

    Dear sirs, thank you for your answers. As far I understand you think, that moving point time will be slow from the stationary point time at any rest. And it will be so if moving point is going to stationary point also from stationary point. OK! But let us consider two simple scenarios. The...
  11. Enovik

    I Twin Paradox - difference between outbound and inbound

    Lorentz formulas are obtained for one simple case: motion in one direction with constant speed. And they are true for this case only. Travelling twin moves in two direction at least: there and back. And two different formulas are needed at least: for there motin and back motion. Time...
Back
Top