Recent content by EonsNearby
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Help with a bijection proof involving sets
I wasn't trying to imply anything bad, like I think the other students are lazy or procrastinators or anything, when I said I assumed most people waited until recently to do this homework. I just thought that since hardly anyone responded, and when I did get a response, it was 2 days ago.- EonsNearby
- Post #78
- Forum: Calculus and Beyond Homework Help
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Help with a bijection proof involving sets
Yeah, I typically find flaws/typos in assignments first since I try to do them as soon as they are assigned. I'm assuming that everyone waited till this day or yesterday to start looking at the assignment.- EonsNearby
- Post #75
- Forum: Calculus and Beyond Homework Help
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Help with a bijection proof involving sets
Well, I'm hoping it is better than this rocky stuff, because this problem has not been kind to my sleep schedule.- EonsNearby
- Post #73
- Forum: Calculus and Beyond Homework Help
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Help with a bijection proof involving sets
The class is Automata, Complexity, and Compatability. I'm a CPSC Information Security and Assurance major, and this is counts as an elective that I need to take to graduate.- EonsNearby
- Post #71
- Forum: Calculus and Beyond Homework Help
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Help with a bijection proof involving sets
I actually sent an e-mail out to everyone in my class asking for help like 3 days ago, but only one person responded and he didn't know how to solve any of the problems in the assignment.- EonsNearby
- Post #69
- Forum: Calculus and Beyond Homework Help
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Help with a bijection proof involving sets
Thank you so much with this, and when I actually write this on notebook paper, I am going to use more symbols. But regarding the counter-example I'm going to show him, someone previously posted the following: I was thinking of using that one, and basically saying something like the...- EonsNearby
- Post #67
- Forum: Calculus and Beyond Homework Help
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Help with a bijection proof involving sets
Well, I will try to re-write the last part using more basic symbols. In order for a function to be onto, for each element y in the range (in this case C U D) there is an element x in the domain (in this case A U B) such that h(x) = y. Now, assume that y ∈ (C U D). y has to be an element from...- EonsNearby
- Post #65
- Forum: Calculus and Beyond Homework Help
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Help with a bijection proof involving sets
I'm basically asking how you were able to input symbols like ∈ into your responses (I just copied that from your previous post btw). If I had known how to put symbols like that (and others) into my responses, I would have done so instead of trying to explain everything using words and very few...- EonsNearby
- Post #63
- Forum: Calculus and Beyond Homework Help
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Help with a bijection proof involving sets
No, that's is the first I've ever heard of LaTex. When we submit our homework to him, we have the option of typing up our answers in a document and submitting that to him, or by doing the work on notebook paper, scanning it, and then e-mailing him the scans. I've been doing the homework on...- EonsNearby
- Post #62
- Forum: Calculus and Beyond Homework Help
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Help with a bijection proof involving sets
Are you just using the symbols in the Quick Symbols box when you reply to a message? If not, then how are you getting the symbols?- EonsNearby
- Post #60
- Forum: Calculus and Beyond Homework Help
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Help with a bijection proof involving sets
What is given: A and C have the same cardinality, so there must be a bijection for A -> C, which I will call f. B and D have the same cardinality, so there must be a bijection for B -> D, which I will call g. Sets A and B have no elements in common because they are disjoint (the intersection...- EonsNearby
- Post #58
- Forum: Calculus and Beyond Homework Help
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Help with a bijection proof involving sets
Okay, then here is another attempt at answering the question from the assignment (assuming the typo is fixed). What is given: A and C have the same cardinality, so there must be a bijection for A -> C, which I will call f. B and D have the same cardinality, so there must be a bijection for B...- EonsNearby
- Post #56
- Forum: Calculus and Beyond Homework Help
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Help with a bijection proof involving sets
I am going to have to continue this tomorrow. Thanks for the help.- EonsNearby
- Post #55
- Forum: Calculus and Beyond Homework Help
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Help with a bijection proof involving sets
Then I think I get it. The only possible elements that x can be is an element from A or B (as you stated in these two lines: Since that is the case, then no element that is not from the domain of A U B -> C U D can be used for x. Now, the method that h uses to map the element of A U B to...- EonsNearby
- Post #53
- Forum: Calculus and Beyond Homework Help
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Help with a bijection proof involving sets
Okay...I hate abstracting but I will try my best...again. So A U B = {1, 2, 3, 4, 5, 6, 7, 8} and C U D = {9, 10, 11, a, b, c, d, e}. First attempt: h(x) = f(x) if x is element 1, 2, 3 OR g(x) if x is element 4, 5, 6, 7, 8. This is one-to-one because every element of A U B is mapped to...- EonsNearby
- Post #50
- Forum: Calculus and Beyond Homework Help