Recent content by EonsNearby
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Proving a bijection between sets
I wasn't trying to imply anything bad, like I think the other students are lazy or procrastinators or anything, when I said I assumed most people waited until recently to do this homework. I just thought that since hardly anyone responded, and when I did get a response, it was 2 days ago.- EonsNearby
- Post #78
- Forum: Calculus and Beyond Homework Help
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Proving a bijection between sets
Yeah, I typically find flaws/typos in assignments first since I try to do them as soon as they are assigned. I'm assuming that everyone waited till this day or yesterday to start looking at the assignment.- EonsNearby
- Post #75
- Forum: Calculus and Beyond Homework Help
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Proving a bijection between sets
Well, I'm hoping it is better than this rocky stuff, because this problem has not been kind to my sleep schedule.- EonsNearby
- Post #73
- Forum: Calculus and Beyond Homework Help
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Proving a bijection between sets
The class is Automata, Complexity, and Compatability. I'm a CPSC Information Security and Assurance major, and this is counts as an elective that I need to take to graduate.- EonsNearby
- Post #71
- Forum: Calculus and Beyond Homework Help
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Proving a bijection between sets
I actually sent an e-mail out to everyone in my class asking for help like 3 days ago, but only one person responded and he didn't know how to solve any of the problems in the assignment.- EonsNearby
- Post #69
- Forum: Calculus and Beyond Homework Help
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Proving a bijection between sets
Thank you so much with this, and when I actually write this on notebook paper, I am going to use more symbols. But regarding the counter-example I'm going to show him, someone previously posted the following: I was thinking of using that one, and basically saying something like the...- EonsNearby
- Post #67
- Forum: Calculus and Beyond Homework Help
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Proving a bijection between sets
Well, I will try to re-write the last part using more basic symbols. In order for a function to be onto, for each element y in the range (in this case C U D) there is an element x in the domain (in this case A U B) such that h(x) = y. Now, assume that y ∈ (C U D). y has to be an element from...- EonsNearby
- Post #65
- Forum: Calculus and Beyond Homework Help
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Proving a bijection between sets
I'm basically asking how you were able to input symbols like ∈ into your responses (I just copied that from your previous post btw). If I had known how to put symbols like that (and others) into my responses, I would have done so instead of trying to explain everything using words and very few...- EonsNearby
- Post #63
- Forum: Calculus and Beyond Homework Help
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Proving a bijection between sets
No, that's is the first I've ever heard of LaTex. When we submit our homework to him, we have the option of typing up our answers in a document and submitting that to him, or by doing the work on notebook paper, scanning it, and then e-mailing him the scans. I've been doing the homework on...- EonsNearby
- Post #62
- Forum: Calculus and Beyond Homework Help
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Proving a bijection between sets
Are you just using the symbols in the Quick Symbols box when you reply to a message? If not, then how are you getting the symbols?- EonsNearby
- Post #60
- Forum: Calculus and Beyond Homework Help
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Proving a bijection between sets
What is given: A and C have the same cardinality, so there must be a bijection for A -> C, which I will call f. B and D have the same cardinality, so there must be a bijection for B -> D, which I will call g. Sets A and B have no elements in common because they are disjoint (the intersection...- EonsNearby
- Post #58
- Forum: Calculus and Beyond Homework Help
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Proving a bijection between sets
Okay, then here is another attempt at answering the question from the assignment (assuming the typo is fixed). What is given: A and C have the same cardinality, so there must be a bijection for A -> C, which I will call f. B and D have the same cardinality, so there must be a bijection for B...- EonsNearby
- Post #56
- Forum: Calculus and Beyond Homework Help
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Proving a bijection between sets
I am going to have to continue this tomorrow. Thanks for the help.- EonsNearby
- Post #55
- Forum: Calculus and Beyond Homework Help
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Proving a bijection between sets
Then I think I get it. The only possible elements that x can be is an element from A or B (as you stated in these two lines: Since that is the case, then no element that is not from the domain of A U B -> C U D can be used for x. Now, the method that h uses to map the element of A U B to...- EonsNearby
- Post #53
- Forum: Calculus and Beyond Homework Help
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Proving a bijection between sets
Okay...I hate abstracting but I will try my best...again. So A U B = {1, 2, 3, 4, 5, 6, 7, 8} and C U D = {9, 10, 11, a, b, c, d, e}. First attempt: h(x) = f(x) if x is element 1, 2, 3 OR g(x) if x is element 4, 5, 6, 7, 8. This is one-to-one because every element of A U B is mapped to...- EonsNearby
- Post #50
- Forum: Calculus and Beyond Homework Help