Recent content by Epiphone

right right, for some reason i thought i was looking at the problem from above. that clears up some things! and for the conservation of energy, initially i think there is only grav potential, and when it is at its lowest point, there is rotational kinetic so that would mean mgh = .5Iw^2 + mgh...

and does this problem make my answer to part c wrong? because i used the initial alpha in my calculation of w^2 = w^2 + 2alpha(delta(theta))

i think radial is V^2/r im a little confused though. why would it be at the "lowest point" if the rotational axis is perpendicular to the page? isn't the height always the same? its instantaneous velocity is tangent to the circular path and perpendicular to the radius, but I am not sure if...

hm, since alpha = a/l alpha = 9g/16Ml so a = 9g/16M? and f = ma, so f = (3M*9g)/16M = 27g/16M? i feel like i am making up rules here :/

ok so you have one puck moving straight to the right initially. this has a certain momentum. this certain momentum is equal to the momentum of both of the pucks after the collision (which you already stated) initial momentum = .35 x 2.3 = .805 to the right (0 degrees) if you know that one will...

Homework Statement Two identical spheres, each of mass M and negligible radius, are fastened to opposite ends of a rod of negligible mass and length 2l. This system is initially at rest with the rod horizontal and is free to rotate about a frictionless, horizontal axis through the center of...

anyone? sorry if bumping is taboo, but i have to go soon! this is my last hope!

im sure that after 6 pages of requests, someone has posted a link online for getting these files HINT HINT

Homework Statement A ring of mass 2.4kg, inner radius 6.0cm, and outer radius 8.0cm is rolling (without slipping) up an inclined plane that makes an angle of theta=36.9 with the horizontal. At the moment the ring is x=2.0 m up the plane its speed is 2.8 m/s. the ring continues up the plane for...

it took a lot of reviewing to find all the little errors i made, but i finally got it to work out thank you very much for all of your help. im glad you gave me that trig identity, I've honestly never learned any of them. perhaps in precalc last year, but I've never used any. thanks again

ok, I'm pretty sure I've done all the math correctly, but I've gotten stuck again i've gotten d by itself: d = [2v^2cos^2(θ)sin(phi)/-gcos^2(phi)] - [2v^2cos^2(θ)sin(θ)cos(phi)/-gcos^2(phi)cos(θ)] i am unsure how to get this into the original form, or if i made a mistake along the way

my second attempt definitely did not work. somehow i lost all of my "v"s I started with: dsin(phi) = vsin(θ)dcos(phi)/vcos(θ) - .5g((dcos(phi)/vcos(θ))^2 and ended up with: d = (sin(phi) - tan(θ)cos(phi)) / (-gcos^2(phi)) should i factor out the dcos(phi)/vcos(θ) initially?

oh wow, you're absolutely right let me re-try this

i see what you mean, but i am having trouble manipulating the variables to isolate d. so far i have: d(sin(phi)) =(visin(θi)vicos(θi))/dcos(phi)-(gvi^2cos^2(θi))/2d^2cos^2(θ))

i am pretty sure that a system in general is whatever you define it to be. i would say that all of them are systems.